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## Question “A gymnast of mass 62.0 kg hangs from a vertical rope attached to the ceiling. You…”

A gymnast of mass 62.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume that the rope does not stretch. Use the value 9.81m/s” for the acceleration of gravity. Part A Calculate the tension T in the rope if the gymnast hangs motionless on the горе. Express your answer in newtons. View Available Hint(s) V ALQ R O ? Submit Part B Calculate the tension T in the rope if the gymnast climbs the rope at a constant rate. Express your answer in newtons. ► View Available Hint(s) IVO AQ R O ?

Calculate the tension T in the rope if the gymnast climbs up the rope with an upward acceleration of magnitude 0.900 m/s. Express your answer in newtons. View Available Hint(s) IP ADM 0 2 ? Submit Part D Calculate the tension T in the rope if the gymnast slides down the rope with a downward acceleration of magnitude 0.900 m/s. Express your answer in newtons. View Available Hint(s) ALQ * R 0 ? Submit

## Answer

There is no acceleration if there is no motion. So, T=my is the gymnast’s weight (9.81 m/s = 1608.22N). If the gymnast climbs at the same rate, there is no net drag on him, so the tension must be equal to his weight. T= mg = 52.2 kg (4.81m/s) = 608. 224) c] Tw=ma = 62 kg (4.81 m/s) = 608.

## Conclusion

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